Question

$x^2(x-1)(x-4)-2x^3=-6x^2$
If x > 0, what is one possible solution to the equation above? (Hint: there are two real solutions)​

Answer 1

Answer:

Answer:

• x = 2 and 5

Step-by-step explanation:

x²(x - 1)(x - 4) - 2x³ = -6x² when x > 0

x²(x - 1)(x - 4) - 2x³ + 6x² = 0

~Use foil to simplify the stuff in parenthesis

x⁴ - 5x³ + 4x² - 2x³ + 6x² = 0

~Combine like terms

x⁴ - 7x³ + 10x² = 0

~Factor

x(x - 2) - 5(x - 2)

~Simplify

(x - 2)(x - 5) = 0

~Solve both factors

x - 2 = 0

x = 2

x - 5 = 0

x = 5

Best of Luck!