Question

$x ^{2} + (x + 2) ^{2} = 290$
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Answer 1

Answer:

Here I have attached your answer

Answer 2

$\huge\underline\pink{SOLUTION}$

$x {}^{2} + (x + 2) {}^{2} = 290$

$x {}^{2} + x {}^{2} + 4 + 4x = 290$

$2x {}^{2} + 4x + 4 = 290$

$x {}^{2} + 2x + 2 = 145$

$x {}^{2} + 2x - 143 = 0$

$x {}^{2} - 11x + 13x - 143$

$x(x - 11) + 13(x - 11) = 0$

$(x - 11)(x + 13) = 0$

$x = 11 \: \: \: and \: \: \: x = - 13$

hope it helps you.