Question

${x}^{2} + x + 5 = 0$
solve by formula method

PLZ ​

Answer 1

Answer:

$x ^{2} + x + 5 \\ a = 1 \: \: \: b = 1 \: \: \:c = 5$

D=b^2-4ac

this implies,D=(1)^2-4(1)(5)

=1-20

=-19

this implies,D is smaller than 0

therefore,the given quadratic equation has no real roots.