Question

$x^2 + x - 56$
factorisation trinomial ​

Answer 1

Answer:

x^2+x-56=0

-56x^2=8x×(-7x)

so

x^2+8x-7x-56=0

X(X+8)-7(X+8)=0

therefore X=-8,7

please mark it as a brainliest answer

Answer 2

Solve

x

2

−

x

−

56

=

0

using the formula

x

0

=

−

b

±

√

b

2

−

4

a

c

2

a

to get solutions

x

0

=

a

and

x

0

=

b

(in this particular case

x

0

=

8

and

x

0

=

−

7

)

Since the original quadratic is equal to zero when

x

is equal to either of the

x

0

values

(

x

−

a

)

and

(

x

−

b

)

are factors of the original quadratic.

Using

a

=

8

and

b

=

−

7

(

x

−

8

)

(

x

+

7

)

=

x

2

−

x

−

56

and the factorization is complete.