Question

${x}^{3} + 27$
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Answer 1

ANSWER :

${x}^{3} + 27 = x {}^{3} + 3 {}^{3} \\ \\ (a {}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} ) \: \: ) \\ \\ = (x + 3)( {x}^{2} - 3x + 9)$

Answer 2

Given:

${x}^{3} + 27$

To find:

the solution

STEP BY STEP EXPLANATION:

${x}^{3} + 27$

write the number in exponential form with an exponent of 3

${x}^{3} + {3}^{3}$

using ${a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} )$ factors the expression

$(x + 3) \times ( {x}^{2} - x \times 3 + {3}^{2} )$

Use the commutative property to the recorder the terms

$(x + 3) \times ( {x}^{2} - 3x + {3}^{2} )$