Chapter: Differentiation
Standard : 12
Answer: y/x
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take log both side
it becomes
logx^3y^4=log (x+y)^7. {:: log a^n =n loga }
3logx+4logy =7log(x+y). {::log ab =log a +log b}
different tiate wrt to dx
3/x+4ydy/dx = 7(1+dy /dx)/(x+y)
okkkkkk
solve it more.
it becomes
logx^3y^4=log (x+y)^7. {:: log a^n =n loga }
3logx+4logy =7log(x+y). {::log ab =log a +log b}
different tiate wrt to dx
3/x+4ydy/dx = 7(1+dy /dx)/(x+y)
okkkkkk
solve it more.
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