Question

$x ^6 - y ^6$

Answer 1

Hope u like my process
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${x}^{6} - {y}^{6} \\ \\ = {( {x}^{3} )}^{2} - {( {y}^{3} )}^{2} \\ \\ = ( {x}^{3} - {y}^{3} )( {x}^{3} + {y}^{3} ) \\ \\ = (( {x})^{3} - ( {y})^{3} )( {(x)}^{3} + {(y)}^{3} ) \\ \\ = ((x - y)( {x}^{2} + xy + {y}^{2} ))((x + y)( {x}^{2} - xy + {y}^{2} )) \\ \\ = (x - y)(x + y)( {x}^{2} + xy + {y}^{2} )( {x}^{2} - xy + {y}^{2} )$
Hope this is ur required answer

Proud to help you

Answer 2

Hi there

Your answer is :-

$x ^6 - y ^6$

$x ^(2\times3) - y ^(2\times3)$

$(x ^3)^2 - ( y ^3)^2$

$(x ^3 - y^3 )\times(x ^3 + y ^3)$

$(x - y)\times(x^2+xy+y^2)\times(x+y)\times(x ^2 - xy + y^2)$

Thank You