FACTORISE BY USING A SUITABLE IDENTITY
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Answered by
20
=>x⁶-y⁶
=>(x²)³-(y²)³
We know that a³-b³=(a-b)(a²+ab+b²)
=>(x²-y²)[(x²)²+x²y²+(y²)²]
=>(x²-y²)(x⁴+x²y²+y⁴)
Answered by
0
x⁶-y⁶
= (x³)²-(y³)²
= (x³+y³)(x³-y³)
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