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Step-by-step explanation:
x√x + (1/x√x) = 9√x + (1/√x)
taking LCM
=> {(x√x)×(x√x) +1 } / x√x = { (9√x)(√x) + 1 } / √x
=> ( x³+1) / x√x =( 9x + 1 )/√x
=> (x³+1) = (9x+1) × x√x / √x
=> (x³+1) = (9x+1)(x)
=> x³+1 = 9x² + x
=> x³-9x²-x+1 = 0
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0
Answer:
IDK
Step-by-step explanation:
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