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Answered by
7
Answer:
(x+y)³-(x³ + y³)
(x³+y³+3x²y+3xy²)-x³ - y³
3xy(x+y)
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Answered by
4
Answer:
(x + y)(3xy)
Step-by-step explanation:
(x + y)³ - (x³ + y³)
Using identity a³ + b³ = (a + b)(a² - ab + b²)
= (x + y)³ - (x + y)(x² - xy + y²)
Taking (x + y) common,
= (x + y)[(x + y)² - (x² - xy + y²)]
Using identity (x + y)² = x² + 2xy + y²
= (x + y)[x² + 2xy +y² - (x² - xy + y²)]
= (x + y)[x² + 2xy +y² - x² + xy - y²)]
= (x + y)(3xy)
Hope this helps! :)
AccioNerd:
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