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Answered by
10
Given that,
x + y = 7 ...(i)
2x - 3y = 9 ...(ii)
Now, (i) × 2 ⇒
2x + 2y = 14 ...(iii)
Now, (iii) - (ii) ⇒
2y + 3y = 14 - 9
⇒ 5y = 5
⇒ y = 1
Now, putting y = 1 in (i), we get
x + 1 = 7
⇒ x = 7 - 1
⇒ x = 6
Therefore, the required solution be
,
#
Answered by
16
hey!
#your solution :
________________
==> X+y = 7............(1)
==> X = 7-y
==> 2x -3y = 9................(2)
now put the Value of X in equation second
then
==> 2(7-y) -3y = 9
==> 14 -2y -3y = 9
==> 14 -5y = 9
==> -5y = 9-14
==> y = -5/-5
==> y = 1
put the Value of X in equation (1)
==> X +1 = 7
==> X = 7-1
==> X = 6 Ans!
✌✌:-):-)☺☺
#your solution :
________________
==> X+y = 7............(1)
==> X = 7-y
==> 2x -3y = 9................(2)
now put the Value of X in equation second
then
==> 2(7-y) -3y = 9
==> 14 -2y -3y = 9
==> 14 -5y = 9
==> -5y = 9-14
==> y = -5/-5
==> y = 1
put the Value of X in equation (1)
==> X +1 = 7
==> X = 7-1
==> X = 6 Ans!
✌✌:-):-)☺☺
satishkumarti5r8t:
Hello
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