![xy2 + x2y + 1 = 0 xy2 + x2y + 1 = 0](https://tex.z-dn.net/?f=xy2+%2B+x2y+%2B+1+%3D+0)
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Explanation:
xy(y+x)=-1
(y+x)=-1/xy
x=-1/xy-y
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Hey mate here is your answer.
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