Question

the length of a rectangle is 5 times its width and the length of its diagonal is 6 square root 26 cm the perimeter of the rectangle is

Answer 1

Answer:

Diagonal =6

l=5b

by Pythagoras theorem,

6^2=l^2+b^2. Eq.1

36= (5b)^2+b^2

36= 6b^2

b^2= 6^2

b=√6

Substitution of value of b in eq.1

36=l^2+6

l^2=30

l=√30

Now perimeter,

2(l+b)= perimeter

2(√30+√6)= perimeter

2(√36)=perimeter

2(6)= perimeter

12= perimeter

Answer 2

Answer:

Step-by-step explanation: