Question

${y}^{2} + 6y = - 9$
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Answer 1

Hey there!

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Answer:

→ $\sf{y^{2} + 6y = -9}$

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Subtracting '-9' from both the sides:

→ $\sf{y^{2} + 6y - (-9) = - 9 - (-9)}$

→ $\sf{y^{2} + 6y + 9 = 0}$

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Factoring left hand side of equation.

→ $\sf{(y + 3)(y + 3) = 0}$

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Now, set the factors equal to zero:

→ $\sf{y + 3 = 0}$

→ ${\boxed{\bold{y = -3}}}$

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Thanks!