Question

$(y + 2 \sqrt3) ^2 - 27$=0
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Answer 1

Answer:

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Step-by-step explanation:

${( {y} + 2 \sqrt{3} )}^{2} - 27 = 0 \\ = > {y}^{2} + {(2 \sqrt{3)} }^{2} + 2.y.2 \sqrt{3} - 27 = 0 \\ = > {y}^{2} + 12 + 4 \sqrt{3} y - 27 = 0 \\ = > = > {y}^{2} + 4 \sqrt{3} y - 15 = 0 \\ = > {y}^{2} + 5 \sqrt{3} y - \sqrt{3} y - 15 = 0 \\ = > y(y + 5 \sqrt{3} ) - \sqrt{3} (y + 5 \sqrt{3} ) = 0 \\ = > (y + 5 \sqrt{3}) (y - \sqrt{3} ) = 0 \\ = > y + 5 \sqrt{3} = 0 \: \: or \: \: \: y - \sqrt{3} = 0 \\ y = - 5 \sqrt{3} \: \: or \: \: y = \sqrt{3}$