Question

$y = x^ sinx$
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Answer 1

Question:-To, differenitaiate y=x^sinx,,with respect to x

Solution:-Simply use chain rule here☺️

y=x^sinx

dy/dx=(sinx)x^(sinx-1)×x'

dy/dx=sinxx^(sinx-1)×1

dy/dx=sinx×x^(sinx-1)

This will be required differenitaiation...

What is chain rule

It is simply a shortcut to obtain differenitaiation of complex terms....

In this first we differentiate taking the whole term then we differenitaiate the number which is in bracket

Same process is done in this question

{hope it helps}