Question

$z {}^{2} - y {}^{2} - 2yz - z {}^{2}$
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Answer 1

Answer:

${z}^{2} - {y}^{2} - 2yz - {z}^{2} \\ = {z}^2 - ( {y}^{2 } + 2yz + {z}^2) \\ = {z}^{2} - {(y + z)}^{2} \\ \\ = (z + y + z)(z - y + z) \\ \\ = (2z + y)(2z - y)$

please mark it BRAINLIEST ✌️

Answer 2

(z^2)-(y^2)-(2yz)-(z^2)

-(y^2)-(2×y×z)

-y^2-2yz

-y×(y+2z)

(-y)(2z+y)

(Or)

z^2-(y^2+2yz+z^2)

z^2-(y+z)^2

(z-y-z)(z+y+z)

(-y)(2z+y)

I hope this helps you and please mark me the brainliast.