Question

Th average for three numbers is 22 then the second number is less than the first number by 6 and third number is greater than the first number by 9 find the first number

Answer 1

Answer:

197

Step-by-step explanation:

Let the first number be 'x', second number be 'y', third number be 'z'.

From question, y=x-6, z=x+9.

Average = (x+y+z)/3

22 = (x+x-6+x+9)/3

22*3 = 3x+3

66 = 3x+3

66-3 = 3x

63 = 3x

63/3 = x

x = 21

So, the first number is 21