Question

Th resistor is 20 = SO 5 +10 A = 3.33 A Rm+R 401 Find the current through 15 Q resistor for the network shown in Fig. 4.88 using Thevenin's 100 ,502 theorem w 31502 12 12 WW 1602 Solution Removing 15 N resistor the open circuit voltage across its terminals is found out in the network of Fig. 4.88(a). The current through 10 S2 resistor is obtained as 200 200 : A= A 10+ 5 13 Voltage across the 10 S2 resistor is given by Va= 200 2000 10 x 15 15 Current through the 12 S2 resistor is found as 200 200 A= A. 28 Voltage across the 12 Q2 resistor is obtained as 200 V Fig. 4.88 Circuit of Ex. 4.61 1012 5Ω a 12 +16 X Vih у​

Answer 1

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