Question

Tha 7th term of an A.p is 32 and 13th term is 62 .Find the A. P.

Answer 1

7th term = 32

a + 6d = 32 ......(1)

13th term = 62

a + 12d = 62 .......(2)

subtract (1) and (2)

6d = 30

d = 5

Now, a = 32 - 6d (from 1)

a = 2

AP IS 2,7,12,17......

Answer 2

let a be the 1st term
and d be common difference
a+6d = 32
=> a=32-6d

a+12d =62
=>32-6d+12d=6232-6d
=>6d=62-32
=>d=30/6=5

a= 32-6d
=32-6*5
= 32-30
=2

AP is 2,7,12....