Tha coordinates of centrid of a triangle is (1,3) and its two vertices are (-7,6) and (8,5) find vertex of tha triangle with solution
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HEY MATE HERE IS YOUR ANSWER
centrid formula for x = x1 +x2+x3/3
and y=y1+y2+y3/3
A ( -7,6) , B (8,5) C ( x3,y3)
(x,y) =(1,3)
x1+x2+x3/3=x
-7+8+x3/3= 1
-1+x3=3
x3=4
and y1+y2+y3/3=3
6+5+y3 /3=3
11+y3 =9
y3 = -2
(x3, y3)=( 4,-2)
area of triangle = 1/2|-7 (5-(-2))+8 (-2-6)+4 (6-5)|
1/2|-7×(-7)+8 (-8)+4 (1)|
1/2|49-64+4|
1/2|53-64|
1/2 ×11
11/2
centrid formula for x = x1 +x2+x3/3
and y=y1+y2+y3/3
A ( -7,6) , B (8,5) C ( x3,y3)
(x,y) =(1,3)
x1+x2+x3/3=x
-7+8+x3/3= 1
-1+x3=3
x3=4
and y1+y2+y3/3=3
6+5+y3 /3=3
11+y3 =9
y3 = -2
(x3, y3)=( 4,-2)
area of triangle = 1/2|-7 (5-(-2))+8 (-2-6)+4 (6-5)|
1/2|-7×(-7)+8 (-8)+4 (1)|
1/2|49-64+4|
1/2|53-64|
1/2 ×11
11/2
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