Question

Tha forces of 4N acts on a body at an angle of 60 degree. find magnitude and direction of the resultant force acting on the body ​

Answer 1

Answer:

Explanation:

your answer is

Given, two force act on a body at angle 60°, exact force is equal to 4 N

so, magnitude of resultant force is -- 42 +42 +2 x 4 x 4 cos(60) 16+ 16 + 32 × = √32 + 16 2

= √48 = 4√3newton

now, let angle between resultant force and vector force is Ø

now,

tan Ø =

4 sin(60)

4 + 4 cos(60)

2√3 6

√3 3 1 √3

ANSWER

So, Ø = 30°

now, let angle between resultant force and vector force is Ø

now,

tan Ø = 4 sin(60) 2√3 4 + 4 cos (60) 6 1 √3 3

So, Ø = 30°

hence, resultant force is 30° from forces 4N

hope it help you