Question

दिलेल्या बहुपदीकरिता p(1), p(0) आणि p(-2) काढा: p(y) = y² - 2y + 5

Answer 1

Solution :

p(y)= y²-2y+5

i ) p(1)= 1² - 2×1 + 5

= 1 - 2 + 5

= 6 -2

= 4

ii ) p(0) = 0 - 2 × 0 + 5

= 5

iii )p(-2) = (-2)² - 2 × (-2) + 5

= 4 + 4 + 5

= 13

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