Question

*दोन समरूप त्रिकोणांच्या संगत भुजांचे गुणोत्तर 2ः5 आहे , लहान त्रिकोणाचे क्षेत्रफळ 64 चौसेमी असेल तर मोठ्या त्रिकोणाचे क्षेत्रफळ किती ?* 1️⃣ 200 चौसेमी 2️⃣ 400 चौसेमी 3️⃣ 800 चौसेमी 4️⃣ 100 चौसेमी​

Answer 1

Answer:

a answer is always right

Answer 2

Solution :-

given that,

→ Ratio of corresponding sides of two similar ∆'s = 2 : 5

→ Area of ∆1 = 64 cm²

since given two ∆'s are similar . Then,

• Ratio of areas of them = Ratio of square of there corresponding sides .

therefore,

→ 64/∆2 = (2/5)²

→ 64/∆2 = 4/25

→ ∆2 = 16 * 25

→ ∆2 = 400 cm² (Ans.)

Learn more :-

*जर △ ABC ~ △ DEF असून AB = 12 सेमी and DE = 14 सेमी. तर △ ABC आणि △ DEF यांच्या क्षेत्रफळाचे गुणोत्तर किती?.*

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In the figure , Line PQ || Side BC AP = 6 , PB = 8 , AQ = x and QC = 12 , then write the value of x.

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