Question

द्विघात बहुपद×2-53×+6 का शून्यक क्या होगा​

Answer 1

SOLUTION

TO DETERMINE

The zeroes of the quadratic polynomial x² - 5x + 6

EVALUATION

Here the given Quadratic polynomial is

x² - 5x + 6

For the zeroes of the polynomial we have

$\sf{ {x}^{2} - 5x + 6 = 0 }$

$\sf{ \implies \: \: {x}^{2} -(3 + 2)x + 6 = 0 }$

$\sf{ \implies \: \: {x}^{2} -3x - 2x + 6 = 0 }$

$\sf{ \implies \: \: x (x - 3) - 2(x - 3)= 0 }$

$\sf{ \implies \: \: (x - 3)(x - 2)= 0 }$

Now x - 3 = 0 gives x = 3

x - 2 = 0 gives x = 2

Hence the required zeroes are 2 and 3

If the polynomial is x² - 53x + 6

Then the zeroes are given by

x² - 53x + 6 = 0

$\displaystyle \sf{ \implies \: x = \frac{ -( - 53) \pm \: \sqrt{ {( - 53)}^{2} - 4.1.6 } }{2.1} }$

$\displaystyle \sf{ \implies \: x = \frac{ 53 \pm \: \sqrt{ 2809 - 24} }{2} }$

$\displaystyle \sf{ \implies \: x = \frac{ 53 \pm \: \sqrt{ 2785} }{2} }$

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