Question

Thank you guys in advance

Answer 1

equation :ax2 + bx + c = 0. We can write:

α = (-b-√b2-4ac)/2a       
         and           
       β = (-b+√b2-4ac)/2a

similarly

x^2-28/6x+C=0
r1=-[28/6-✓(28/6)^2-4*1*C]
r1=[14/3-✓(14*14-9*4C)/3]
r1=[14-✓(196-36C)]/3

r2=-[28/6+✓(28/6)^2-4*1*C]
r2=[14+✓(196-36C)]/3

r1=6r2

therefore[14-✓(196-36C)]/3=6[14+✓(196-36C)]/3 [14-✓(196-36C)]
6[14+✓(196-36C)]

e-f=6(e+f)
7f=5e

7✓(196-36C)=5*14
196-36C=70/7
196-10=36C
186/36=C
5.167

Answer 2

Answer:

:)

Step-by-step explanation:

r1=-[28/6-✓(28/6)^2-4*1*C]

r1=[14/3-✓(14*14-9*4C)/3]

r1=[14-✓(196-36C)]/3

r2=-[28/6+✓(28/6)^2-4*1*C]

r2=[14+✓(196-36C)]/3

r1=6r2