Question

that product of two numbers is 2028 and there hcf is 13 the numbers of such pairs​

Answer 1

Answer

The product of two numbers is 2028 and their HCF is 13. The number of such pairs is :

[A]1

[B]2

[C]3

[D]4

2

Here, HCF = 13

Let the numbers be 13x and 13y, where x and y are prime to each other.

Now, 13x \times 13y = 2028

=> xy = \frac{2028}{13\times 13} = 12

The opposite pairs are : (1, 12), (3, 4), (2, 6)

But the 2 and 6 are not co-prime.

So, required no. of pairs = 2

Hence option [B] is correct answer.

Answer 2

Step-by-step explanation:

that product of two numbers is 2028 and there hcf is 13 the numbers of such pairs