In ABC. LACO = 90°. Seg CDI seg AB and seg
CE is angle bisector of LACB.
Prove that
AD
BD
BE2
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In δAbc , ∠Acb = 90°. Seg Cd ⊥ Side Ab and Seg Ce is Angle ...
In δAbc , ∠Acb = 90°. Seg Cd ⊥ Side Ab and Seg Ce is Angle Bisector of ∠ Acb
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