Question

that sin square theta + cos square theta is equal to 1
​

Answer 1

Answer:

The given equation Sin^2 \theta + Cos^2 \thetaSin

2

θ+Cos

2

θ = 1 is proved.

Step-by-step explanation:

Given:

Prove that sin square theta + cos square theta is equal to 1

Solution:

Put sin \theta = \frac{P}{H}sinθ=

H

P

, cos \theta = \frac{B}{H}cosθ=

H

B

,

Sin^2 \theta + Cos^2 \thetaSin

2

θ+Cos

2

θ = 1

(\frac{P}{H})^2 + (\frac{B}{H})^2(

H

P

)

2

+(

H

B

)

2

= 1

\frac{(P^2 + B^2)}{H^2}

H

2

(P

2

+B

2

)

= 1

Ina triangle, by pythogoras,

P^2 + B^2 = H^2P

2

+B

2

=H

2

Hence, \frac{H^2}{H^2}

H

2

H

2

= 1.

Hence proved

Hope this helps you