The 0.18 gram of a divalent metal was completely dissolved in 100 ml of 1.28 N HCl solution . The volume was then made up to 200 ml. 50 ml of this solution required 54.6 ml of 0.22 n NaOH solution for complete neutralization . Find the equivalent weight of metal.
Answers
Given,
0.9gms metal requires 100ml of 1N HCl
⇒ Volume of HCl=100ml
Normality of HCl=1N
⇒ Weight of HCl=
1000
N.Eq.Wt×V
[∵ Normality formula] =
1000
1×1×100
=0.1gm
We know, Equivalent Weight of Metal is the mass of metal required to produce 1gm of H
2
⟶(1)
Also, We know 0.1gm of HCl gives 0.1gm H
2
⇒ 1gm HCl Gives 1gm H
2
Now, if 0.9gm metal requires 0.1gm HCl
⇒1gm HCl will require
0.1
1×0.9
gm metal
∴ Mass of metal which produces 1gm H
2
=9gm
∴ From (1) Equivalent Weight of Metal= 9gm
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