Question

The 10th and 18th term of an AP are 41 and 73 find 26th term

Answer 1

Hi Friend ✋✋

a10 = a + 9d = 41 .........(1)
a18 = a + 17d= 72.........(2)


(1) - (2)


a - a + 9d - 17d = 41 -73

8d = 32

d = 4

a + 36 = 41

a = 5


then a26 = 5 + 25 × 4 = 5 + 100 = 105


hope it helps

Answer 2

"The 26th term will be 105.

Given:

10th term = a + 9d = 41

18th term = a + 17d= 72

To find:

26th term

Solution:

10th term = a + 9d = 41 .........(1)

18th term = a + 17d= 72 .........(2)

(1) - (2)

a - a + 9d - 17d = 41 -73

8d = 32

d = 4

a + 36 = 41

a = 5

then the 26th term will be

26th term = a+25d $= 5+ 25 \times 4=5+100= 105$

Then the 26th term will be 105."