the 10th term and 4th term of an AP are 125 and 0.find the sum of first 35 terms??
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Given The 10th term and 4th term of an AP are 125 and 0.find the sum of first 35 terms??
- Given 10 th term is 125
- 4 th term is 0
- So we get the equations as
- a + 9d = 125 ----------------1
- a + 3d = 0 -------------------2
- subtracting the equations we get
- 6d = 125
- Or d = 125/6
- Substituting d in equation 2 we get
- So a + 3 (125/6) = 0
- Or a = - 125 / 2
- Now we know that sum to n terms is given by
- Sn = n/2 [2a + (n – 1)d]
- = 35/2 [2 (-125/2 + (35 – 1) 125/6]
- = 35/2 [- 125 + 708.33]
- = 35/2 x 583.3
- = 10,208.33
So S35 = 10,208.33
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