Question

The 10th term of an arithmetic sequence exceeds 30 than its 4th term
What is its common difference

Answer 1

Let the 1st term of the A.P be a and the common difference be d.

So,the series is a, a+d, a+2d.......

Nth term of A.P =a+(n-1)d

10th term of A.P= a+9d

4th term of A.P= a+3d

Give, 10th term of A.P is 30 more than the 4th term.

a+9d= a+4d+30

3d=30

d=10

Common difference of A.P is 10.

Answer 2

Answer:

The common difference of A.P. is 10.

Step-by-step explanation:

Let the first term of A.P. be and the common difference be d.

So, the series will become a, a + d, a + 2d...

nth term of A.P = a + (n - 1) d

10th term of A.P. = a + 9d

4th term of A.P. = a + 3d

Given, 10th term of A.P. is 30 more than the 4th term.

$\Longrightarrow \: a + 9d = a + 4d + 30 \\ \Longrightarrow \:3d = 30 \\ \Longrightarrow \:d = 10$

Hence, common difference of A.P. is 10.