The 10th term of an arithmetic sequence is 82 and its common difference is 8. what is the position of the term 250 in this sequence
Answers
Answered by
6
Step-by-step explanation:a+9d=82
d=8.
so, a+9(8)=82
a+72=82
a=10
d=8
an=a+(n-1)d
250=10+(n-1)8
250=10+8n-8
250=2+8n
8n=250-2
8n=248
n=248/8
n=31
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Answered by
14
a+9d=82
d=8.
so, a+9(8)=82
a+72=82
a=10
d=8
an=a+(n-1)d
250=10+(n-1)8
250=10+8n-8
250=2+8n
8n=250-2
8n=248
n=248/8
n=31
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