Question

the 10th term of the AP:5,8,11,14.........is

Answer 1

$a = 5 \\ d = 8 - 5 \\ \\ = > 3 \\ \\ \\ \\ now \: 10th \: term = > \\ \\ \\ a + (n - 1) \times d \\ \\ \\ 5 + (10 - 1) \times 3 \\ \\ \\ 5 + 9 \times 3 \\ \\ = > 5 + 27 \\ \\ \\ = > 32$
HOPE IT HELPS!!!!


THANKS

Answer 2

Answer:

$\huge{\boxed{\boxed{\sf{a10=32}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION-}}}}}$

□a=5

□d=a2-a1

c.d=8-5=3

$an = a + (n - 1) \times d \\ a10 = 5 + (10 - 1) \times 3 \\ = )5 + 9 \times 3 \\ = )5 + 27 \\ = )32$

>>Short method:

$a10 = a + 9d \\ = )5 +9 \times 3 \\ = )5 +9 \times 3 \\ = )5 + 27 \\ = )32$

$\huge{\boxed{\boxed{\sf{a10=32}}}}$