Math, asked by babuprincy6, 6 months ago

The 11 th term of an arithmetic sequence is 58 and 31 term is 158.write the arithmetic sequence​

Answers

Answered by MisterIncredible
7

Given : -

The 11th term of an arithmetic sequence is 58 .

31st term of an arithmetic sequence is 158 .

Required to find : -

  • Arithmetic progession ?

SoLuTiOn : -

11th term = 58

31st term = 158

We need to find the arithmetic progession ?

So,

We know that ;

The 11th term of an arithmetic sequence can be represented as " a + 10d "

The 31st term of an arithmetic sequence can be represented as " a + 30d "

This implies ;

a + 10d = 58 \longrightarrow{\tt{ Equation - 1}}

Consider this as equation - 1

a + 30d = 150 \longrightarrow{\tt{ Equation - 2}}

Consider this as equation - 2

Now,

We need to solve these 2 equations simultaneously .

Let's use Elimination method . So, that by eliminating one variable we can simplify our calculations .

Subtract equation 1 from equation 2

 \tt a + 30d  =  158 \\ \tt a + 10d  = 58    \\ \underline{ ( - )(  - ) \:  \: ( - ) \:  \:  \:  \: } \\  \:  \: \tt \:   \:   + 20d = 100 \\  \\  \implies \sf 20d = 100 \\  \\  \implies \sf d =  \frac{100}{20}  \\  \\  \implies \sf d = 5

Substitute the value of d in Equation 1

=> a + 10d = 58

=> a + 10(5) = 58

=> a + 50 = 58

=> a = 58 - 50

=> a = 8

Hence,

  • Common difference ( d ) = 5

  • First term ( a ) = 8

Now,

Let's form the AP ;

 \to \mathsf{1st \: term \:  = a =  \boxed{ 8}} \\  \\  \to \mathsf{2nd \: term = a + d = 8 + 5 =  \boxed{13}} \\  \\  \to \mathsf{3rd \: term = a + 2d = 8 + 2(5)  = 8 + 10 =  \boxed{18}} \\  \\ \to \mathsf{ 4th \: term  = a + 3d = a + 3(5) = 8 + 15 =  \boxed{23}}

AP = 8 , 13 , 18 , 23 . . . . . . . . . . . .

Required AP !

AP = 8 , 13 , 18 , 23 , . . . . . . . .

Additional Information

Question

What is an Arithmetic progession ?

Answer

An arithmetic progession is a sequence of terms whose common difference is constant/equal .

Example :

  • 2 , 4 , 6 , 8 , 10 . . . . . . .

  • 1 , 3 , 5 , 7 , 9 . . . . . .

These are some examples of AP

Question

How to identify whether the given sequence is an AP or not ?

Answer

To identify whether any given sequence is an AP or not . We need to find the common difference between the terms . If the difference is constant then it is an AP .

The trick is ;

Common difference = ( 2nd term - 1st term ) = ( 3rd term - 2nd term )

Formulae related to arithmetic progession ;

To find the nth terms of the AP is

\boxed{\tt{ {a}_{nth} = a + ( n - 1 ) d }}

To find the sum of n terms of the AP is

\boxed{\tt{ {S}_{nth} = \dfrac{n}{2} [ 2a + ( n - 1 ) d ] }}

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