The sum of a digit of a two digit number is 12 . If 18 is added to it .. and when the digits are reversed ...find the number? ( ⇒VERY IMPORATANT..) (⇒PLZ EXPLAIN AS STEPS...AND ALSO THE REASONS) (⇒IF MENTIONED THE CONDITIONS ABOVE THE ANSWER WILL BE MAKED AS THE BRAINLIST ANSWER)
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Step-by-step explanation:
Let the unit's digit be x and the ten's digit be y.
Sum of the digits of a two digit number is given to be 12.
x + y = 12 …….(i)
Original number = 10y + x
Number obtained on reversing the digits = 10x + y
According to the question:
10y + x + 18 = 10x + y
9x - 9y = 18
x - y = 2 …….(ii)
(i) and (ii) are the required equations.
subtract (ii) from (i)
you will get,
2y=10
y=5
x=7
so 75 or 57 would be the answer
but please check the answer once again i am not sure
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