Question

The 11th term of the AP: -5,-5/2,0,5/2,.. is

Answer 1

Answer:

A = -5

D = 5/2

Tn = 11

Therefore,

Tn = a + 10d

= -5 + 10 × 5/2

= -5 + 25

= 20

So the 11th of an AP is 20.

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Answer 2

11th term of AP: -5,-5/2,0,5/2,.. is 20.

Given:

• An A.P.
• -5,-5/2,0,5/2,..

To find:

• Find the 11th term.

Solution:

Formula\concept to be used:

General term of AP: $\bf a_n = a + (n - 1)d$

here,

a: First term

d: Common difference

n: number of term

Step 1:

Find the values of terms used in formula.

$\bf a = - 5$

$d = \frac{ - 5}{2} - ( - 5)$

or

$d = \frac{ - 5}{2} + 5$

or

$d = \frac{ - 5 + 10}{2}$

or

$\bf d = \frac{ 5}{2}$

and n= 11.

Step 2:

Put the values in formula.

$a_{11}= - 5 +\left( (11 - 1) \times \frac{5}{2}\right)$

or

$a_{11}= - 5 +\left( 10 \times \frac{5}{2}\right)$

or

$a_{11} = - 5 +( 5 \times 5)$

or

$a_{11} = - 5 + 25$

or

$\bf a_{11} = 20$

Thus,

11 th term of AP is 20.

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