The 12 term of an A.P x, 4x/3,5x/3,2x........is
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The 12th term of the AP would be 14x/3.
Given
- A.P
- x, 4x/3,5x/3,2x....
To find
- 12 term of an A.P
Solution
we are provided with an ap and I asked to find the 12th the term of the arithmetic progression
first we have to find the common difference of the arithmetic progression
d = 4x/3 - x
or, d = (4x-3x)/3
or, d = x/3
12th term of the arithmetic progression,
an = a + (n-1)d
or, a_12 = x + (12-1)x/3
or, a_12 = x + 11x/3
or, a_12 = (3x+ 11x)/3
or, a_12 = 14x/3
Therefore, the 12th term of the AP would be 14x/3.
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