the 12th term of an ap exceeds the third term by 36 if the 16th term is 64 determine the series
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Answered by
14
Answer:
Heres your answer
12th term of AP= 3rd term + 36
a+11d= a+2d+36
11d-2d=36
9d=36
d= 36/9= 4
So a will be
16th term of AP= 64
a+15d=64
a+60=64
a=64-60=4
SO THE SERIES IS AS FOLLOWS
AP::: 4, 8,12,16,20,24....
Hope it helps ✌
Answered by
0
Answer:
kise kya hai
Step-by-step explanation:
11 d kise aya
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