the 13th term of AP is 26 then sum of 25 terms
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a13 = 26
a+(n-1)d=26
a+ (13-1)d=26
a+12d = 26 ....(i)
Then,
s25= n/2{2a + (n-1)d}
=25/2{2a+24d}
a+(n-1)d=26
a+ (13-1)d=26
a+12d = 26 ....(i)
Then,
s25= n/2{2a + (n-1)d}
=25/2{2a+24d}
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