the 13th term of so is four its3rd term. if it's fifth term is 16 then find the sum of its first ten terms
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Given, 13th term is 4 its 3rd term.
= a + 12d = 4(a+2d)
4d = 3a ---------------- (1)
Given, 5th term is 16
= a+4d = 16 (In (1) 4d = 3a)
= a + 3a = 16
a = 4
Substitute a=4 in (1), we get d = 3
We should calculate sum of 1st 10 terms = n/2(2a+(n-1)d)
= 10/2(2a+9d)
= 5(8+27)
= 175.
Hope this helps!
= a + 12d = 4(a+2d)
4d = 3a ---------------- (1)
Given, 5th term is 16
= a+4d = 16 (In (1) 4d = 3a)
= a + 3a = 16
a = 4
Substitute a=4 in (1), we get d = 3
We should calculate sum of 1st 10 terms = n/2(2a+(n-1)d)
= 10/2(2a+9d)
= 5(8+27)
= 175.
Hope this helps!
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