Question

The 14th term of an ap is twice its 8th term if the 6th term is minus 8 then find the sum of its first 20 terms

Answer 1

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Answer 2

Answer:

Given,

a6 =−8

a+(6−1)d=−8

a+5d=−8

a=−8−5d

T

14

=2T

8

a+13d=2(a+7d)

a+13d=2a+14d

a=−d

−8−5d=−d

−8=4d

d=−2

a=2

s

20

=

10

20

(2+2+(20−1)(−2))

=10(4+19(−2))

=10(4−38)

=−340

Step-by-step explanation:

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