The 15 th term of an
a.p. is 3 more than twise its 7th term . if the 10 th term of the
a.p.is 41 ,find its nth term
Answers
Answered by
1
Hey dear here is your answer!!!!!!!
According to question:-
A15 = 2(A7) + 3
a + 14d = 2(a + 6d) + 3
a + 14d = 2a +12d + 3
-3 = a -2d
a = -3 + 2d .....eq(1)
A10 = 41
a + 9d = 41
substitute value of a from eq.(1)
-3+2d + 9d = 41
11d = 44
d = 4
a = 5
An = a + (n-1)d
= 5 + (n-1)4
Hope it helps u dear...☺️☺️☺️☺️
According to question:-
A15 = 2(A7) + 3
a + 14d = 2(a + 6d) + 3
a + 14d = 2a +12d + 3
-3 = a -2d
a = -3 + 2d .....eq(1)
A10 = 41
a + 9d = 41
substitute value of a from eq.(1)
-3+2d + 9d = 41
11d = 44
d = 4
a = 5
An = a + (n-1)d
= 5 + (n-1)4
Hope it helps u dear...☺️☺️☺️☺️
Answered by
0
let first term of a.p =a . by q. a+14d=a+6d+3. d=3/8. and a+9d =41. a+27/8=41. 8a=328-27. a=281/8. then final nth term is an=281/8+(n-1)3/8.ans..
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