the 15th term of an ap is 26 and its tenth term is 51 find ap
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a15= 26
=>. a+ 14d =26........(1)
a10=51
=>. a+9d=51.........(2)
subtract eq (1) from (2)
a+9d-a-14d=51-26
-5d=25
d= -5
put d= -5 in eq (1)
a+ 14*(-5)=26
a-70=26
a=26+70
a=96
so the ap is
a,a+d,a+2d...
96,91,86.....
hope this will help u......
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