Question

the 15th term of an ap is 26 and its tenth term is 51 find ap​

Answer 1

a15= 26

=>. a+ 14d =26........(1)

a10=51

=>. a+9d=51.........(2)

subtract eq (1) from (2)

a+9d-a-14d=51-26

-5d=25

d= -5

put d= -5 in eq (1)

a+ 14*(-5)=26

a-70=26

a=26+70

a=96

so the ap is

a,a+d,a+2d...

96,91,86.....

hope this will help u......