Question

The 15th term of an AP is 3 more than twice its 7th term. If the 10th term
of the AP is 41, then find its nth term.
​

Answer 1

Step-by-step explanation:

nth term is 5 + 4n - 4

according to question :

a+14d = 2(a+6d)+3

a+14d=2a+12d+3

-a+2d=3 ------ (1)

a+9d=41 ------ (2)

Adding (1) and (2)

11d=44

d=4

Substituting the value of d in (1)

we get

a=5

so,

a+(n-1)d

5+(n-1)4

5+4n-4 ----------- answer

Hope it helps