the 16 term of an ap 3,7,9,11 i
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Answer: 63
Step-by-step explanation:
Here we need to find the 16th term so n becomes 16 a the first term of ap becomes 3 and the difference d is equal to 4.
a = 3 ; d = 7-3 = 4; n = 16
We know the formula to find the nth term which is
t_(nth) = a + (n-1)d
By substituting the values we get
t16 = 3 +(16-1)4
= 3 + (15 x 4)
=3 + 60
= 63
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