The 17th term of an A P exceeds its 10th term by 7. Find the common difference .
Answers
Answered by
1
Answer:
a+(n-1)d
= a+(17-1)d
= a+16d
a+(n-1)d
= a+(10-1)d
= a+9d
ATP:
(a+16d)-(a+9d) = 7
a+16d-a-9d = 7
7d = 7
d = 7/7
d = 1
Common difference will be 1
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Answer:
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