the 17th term of an AP exceeds it's 10th term by 7 find the common difference
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an = a+(n-1)d
a17=a=16d ( 1) - a
10 = a + 9d ( 2) -
a17-a10=7- -
(a+16d)-(a+9d)= -
7d= 7- d= 1
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