Question

The 17th term of an AP exceeds its 10th term by 7. Find the common difference.

Answer 1

a+16d=a+10d+7
6d=7
d=7/6

Answer 2

Solution :

Let a be the first term and d the common difference.

It is given       $a_{17} - a_{10} = 7$

⇒ (a + 16d) - (a + 9d) = 7

⇒                          7d = 7  

⇒                            d = 1

Thus, the common difference is 7.